Giả sử hh chỉ gồm Na
\(2Na+2HCl\rightarrow2NaCl+H_2\)
\(n_{Na}=\frac{6,2}{23}=\frac{31}{115}\left(mol\right)\)
\(\Leftrightarrow n_{NaCl}=n_{Na}=\frac{32}{115}\left(mol\right)\)
\(\Rightarrow m=m_{NaCl}=\frac{32}{115}.58,5=15,77\left(g\right)\)
Giả sử hh chỉ gồm K
\(2K+2HCl\rightarrow2KCl+H_2\)
\(n_K=\frac{6,2}{39}=\frac{31}{195}\left(mol\right)\)
\(\Rightarrow n_{KCl}=\frac{31}{195}\left(mol\right)\)
\(\Rightarrow m=m_{KCl}=\frac{31}{195}.74,5=11,84\left(g\right)\)
\(\Rightarrow11,84< m< 15,77\)
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