\(a.\)
Theo tăng giảm khối lượng :
\(n_{hh}=\dfrac{21.6}{96-60}=0.6\left(mol\right)\)
\(n_{CO_2}=n_{hh}=n_{H_2O}=0.6\left(mol\right)\)
Bảo toàn nguyên tố H :
\(n_{H_2SO_4}=0.6\left(mol\right)\)
\(m_{dd_{H_2SO_4}}=\dfrac{0.6\cdot98}{24.5\%}=240\left(g\right)\)
\(b.\)
\(V_{CO_2}=0.6\cdot22.4=13.44\left(l\right)\)