\(kl_1=X;kl_2=Y\)
Vì \(kl\in IIA\rightarrow X\left(II\right),Y\left(II\right)\)
Đặt \(X< R< Y\)
\(PTHH:R+2HCl\rightarrow RCl_2+H_2\)
Theo pt:
\(\Rightarrow n_R=\frac{3,36}{22,4}=0,15\left(mol\right)\)
\(\Rightarrow M_R=\frac{4,4}{0,15}=29,\left(3\right)\)
\(\Rightarrow X< 29,3< Y\)
\(\Rightarrow\left\{{}\begin{matrix}X:Mg\left(Magie\right)\\Y:Ca\left(Canxi\right)\end{matrix}\right.\)
\(n_{HCl}=0,3\left(mol\right)\rightarrow\sum n_{HCl}=0,3+0,3.30\%=0,39\left(mol\right)\)
( s lại là C%, phải là V chứ?)
\(\rightarrow V_{HCl}=\frac{0,39}{1}=0,39\left(l\right)=390\left(ml\right)\)
Đúng 0
Bình luận (0)
