\(PTHH:CaO+2H_2O\rightarrow Ca\left(OH\right)_2+H_2\)
Ta có:
\(n_{Ca}=\frac{40}{40}=1\left(mol\right)\)
\(\Rightarrow n_{H2}=n_{Ca}=1\left(mol\right)\)
\(\Rightarrow V_{H2}=1.22,4=22,4\left(l\right)\)
\(n_{Ca\left(OH\right)2}=n_{Ca}=1\left(mol\right)\Rightarrow m_{Ca\left(OH\right)2}=1.74=7,4\left(g\right)\)
\(2H_2+O_2\rightarrow2H_2O\)
\(\Rightarrow n_{O2}=\frac{1}{2}n_{H2}=\frac{1}{2}.1=0,5\left(mol\right)\)
\(\Rightarrow V_{O2}=0,5.22,4=11,2\left(l\right)\)
\(\Rightarrow V_{kk}=5V_{O2}=11,2.5=56\left(l\right)\)