Ta có \(\frac{NA}{NB}=\frac{3}{2}\left(gt\right)\) => \(\frac{NA}{NB+NA}=\frac{3}{3+2}\Rightarrow\frac{NA}{AB}=\frac{3}{5}\)
=> NA= \(\frac{3}{5}AB=\frac{3}{5}.6=3,6\left(cm\right)\)
=> NB = AB - NA = 6 - 3,6 = 2,4 (cm)
Ta có \(\frac{MA}{MB}=\frac{3}{2}\left(gt\right)\) => \(\frac{MA-MB}{MB}=\frac{3-2}{2}\Rightarrow\frac{AB}{MB}=\frac{1}{2}\)
=> MB = 2.AB = 2.6 = 12 (cm)
=> MA = MB + AB = 6 + 12 = 18 (cm)