CH3COOH + NaHCO3 => CH3COONa + CO2 + H2O
nH2 = V/22.4 = 4.48/22.4 = 0.2 (mol)
Theo phương trình suy ra: nCH3COOH = 0.2 (mol)
mCH3COOH = n.M = 0.2 x 60 = 12 (g)
mC2H5OH = 30.4 - 12 = 18.4 (g)
%CH3COOH = 39.47%, %C2H5OH = 60.57%
nCO2= 0.2 mol
CH3COOH + NaHCO3 --> CH3COONa + CO2 + H2O
0.2_________________________________0.2
mCH3COOH= 12g
mC2H5OH= 18.4g
%CH3COOH= 39.47%
%C2H5OH= 60.53%