\(Fe+2HCl\rightarrow FeCl_2+H_2\)
\(FeCO_3+2HCl\rightarrow FeCl_2+CO_2+H_2O\)
a)
Theo quy tắc đường chéo
\(\Rightarrow n_{H2}=2n_{CO2}\)
\(\%V_{H2}=\frac{1}{3}.100=33,33\%\)
\(\%V_{CO2}=100\%-33,33\%=66,67\%\)
b)
Gọi a là số mol Fe b là số mol FeCO3
Giải hệ PT:
\(\left\{{}\begin{matrix}a=2b\\56a+116b=22,8\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}a=0,2\\b=0,1\end{matrix}\right.\)
\(m_{Fe}=0,2.56=11,2\left(g\right)\)
\(m_{FeSO3}=0,1.116=11,6\left(g\right)\)
c)
\(n_{HCl}=0,5.2=1\left(mol\right)\)
\(\Rightarrow n_{HCl_{du}}=0,1-0,3.2=0,4\left(mol\right)\)
\(CM_{HCl}=\frac{0,4}{0,5}=0,8M\)
\(CM_{FeCl2}=\frac{0,3}{0,5}=0,6M\)
