\(CO_2\left(0,1\right)+Ca\left(OH\right)_2\left(0,1\right)\rightarrow CaCO_3+H_2O\)
\(n_{CO_2}=0,1\left(mol\right)\)
\(\Rightarrow n_{Ca\left(OH\right)_2}=0,1\left(mol\right)\)
\(\Rightarrow C_{M_{Ca\left(OH\right)2}}=\dfrac{0,1}{0,2}=0,5\left(M\right)\)
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CO2(0,1)+Ca(OH)2(0,1)→CaCO3+H2OCO2(0,1)+Ca(OH)2(0,1)→CaCO3+H2O
nCO2=0,1(mol)nCO2=0,1(mol)
⇒nCa(OH)2=0,1(mol)⇒nCa(OH)2=0,1(mol)
⇒CMCa(OH)2=0,10,2=0,5(M
