\(n_{CO2}=0,1\left(mol\right);\%_{Na2CO3}=53\%\)
\(2NaOH+2HCl\rightarrow2NaCl+H_2O\)
\(Na_2CO_3+2HCl\rightarrow2NaCl+CO_2+H_2O\)
0,1________________________0,1___________
Vì có 1 pt có CO2 nên ghép mol CO2
\(\%m_{Na2CO3}=\frac{0,1.106}{20}.100\%=53\%\)