2CH3COOH + Na2CO3 => 2CH3COONa + CO2 + H2O
nCH3COOH = 0.2 x 2 = 0.4 (mol)
Theo pt => nCO2 = 0.2 (mol)
VCO2 = 22.4 x n = 22.4 x 0.2 = 4.48 (l)
mNa2CO3 = n.M = 106 x 0.2 = 21.2 (g)
mdd Na2CO3 = 21.2 x 100/10 = 212 (g)
CM = n/V <=> 0.5 = 0.4/V
=> V = 0.8 (l) = 800 ml
Thêm vào 600 ml nước (800-200)