NaCO3 + 2HCl ->2NaCl+ CO2 +H2O
nNaCO3=200:106 =1,88 mol
theo pthh nCO2=nNaCO3 =1,88 mol
=>mCO2=1,88.44= 82,72 g
mdd sau pu =200+120-82,72 =237,28 g
mNaCl=237,28.20:100=47,456g
nNaCl=47,456:58,5=0,81 mol
theo pthh nHCl =nNaCl=0,81 mol
nNaCO3=1/2n NaCl =0,405 mol
C%NaCO3=[0,405.83]:200.100=16,8075 %
C%HCl=[0,81.36,5]:120.100=0,29 %