\(m_{H2SO4}\)= \(\dfrac{C\%.mdd_{H2SO4}}{100\%}\)=\(\dfrac{19,6.200}{100\%}=39,2\left(g\right)\)
\(n_{H2SO4}=\dfrac{m}{M}=\dfrac{39,2}{98}=0,4\left(mol\right)\)
\(H_2SO_4+BaCl_2->2HCl+BaSO_4\downarrow\)
0,4 0,4 0,8 0,4 (mol)
a) \(m_{BaCl_2}=n.M=0,2.208=41.6\left(g\right)\)
\(C\%=\dfrac{m_{BaCl_2}.100\%}{mdd}=\dfrac{41,6.100}{200}=20,8\left(\%\right)\)
b)\(m_{BaSO_4}=n.M=0,4.233=93,2\left(g\right)\)
c)\(m_{HCl}=n.M=0,8.36,5=29,2\left(g\right)\)
\(m_{ddsau}=m_{ddthamgia}\)
\(m_{HCl}=200+200=400\left(g\right)\)
\(C\%=\dfrac{29,2.100\%}{400}=7,3\left(\%\right)\)
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