nhớ tick mình
chúc bn học tốt
\(MnO_2+4HCl\rightarrow MnCl_2+Cl_2+2H_2O\)
\(Cl_2+2NaOH\rightarrow NaCl+NaClO+H_2O\)
Ta có :
\(n_{MnO2}=\frac{17,4}{87}=0,2\left(mol\right)\Rightarrow n_{Cl2}=0,2\left(mol\right)\)
\(n_{NaOH}=\frac{145,8.20\%}{40}=0,729\left(mol\right)\)
\(n_{NaOH.trong,A}=0,729-0,2.2=0,329\left(mol\right)\)
\(m_{dd\left(spu\right)}=0,2.71+145,8=160\left(g\right)\)
\(C\%_{NaOH}=\frac{0,329.40}{160}.100\%=8,225\%\)
\(C\%_{NaCl}=\frac{0,5.58,5}{160}.100\%=7,3125\%\)
\(C\%_{NaClO}=\frac{0,2.74,5}{160}.100\%=9,3125\%\)
