Ta có:
\(n_{Zn}=\frac{13}{65}=0,2\left(mol\right)\)
\(PTHH:Zn+2CH_3COOH\rightarrow\left(CH_3COO\right)_2Zn+H_2\)
________0,2_____0,4_____________________
\(CH_3COOH+NaOH\rightarrow CH_3COONa+H_2O\)
0,4___________0,4____________________
\(m_{NaOH}=0,4.40=16\left(g\right)\)
\(m_{dd\left(NaOH\right)}=\frac{16.100}{10}=160\left(g\right)\)