2CH3COOH + Na2CO3 => 2CH3COONa + CO2 + H2O
nCO2 = V/22.4 = 11.2/22.4 = 0.5 (mol)
Theo phương trình ==> nCH3COOH = 0.5 x 2 = 1 (mol)
mCH3COOH = n.M = 1 x 60 = 60 (g)
mC2H5OH = mhh - mCH3COOH = 120 - 60 = 60 (g)
mNaOH = 100x20/100 = 20 (g)
nNaOH = m/M = 20/40 = 0.5 (mol)
nNaOH/nCO2 = 1 ==> thu muối HCO3
NaOH + CO2 => NaHCO3
Theo pt: nNaHCO3 = 0.5 (mol)
mNaHCO3 = n.M = 0.5 x 84 = 42 (g)