\(a,PTHH:Na_2CO_3+2HCl\rightarrow2NaCl+H_2O+CO_2\)
\(n_{CO2}=\frac{1,12}{22,4}=0,05\left(mol\right)\)
\(\rightarrow m_{Na2CO3}=0,05.106=5,3\left(g\right)\)
\(m_{Na2SO4}=10-5,3=4,7\left(g\right)\)
b, Đổi 200ml = 0,2l
\(\rightarrow CM_{HCl}=\frac{0,2}{0,1}=2M\)