Question

câu 1:

khối lượng theo gam cua nguyên tử oxi

Answer 1

Như ta đã biết: \(1đvc=1,6605^{-24}\)

mà \(NTKO=16đvc\)

\(\Rightarrow m_O=1,6605.10^{-24}.16=2,6568.10^{-23}\)

Answer 2

https://i.imgur.com/dDJex3x.jpg

Answer 3

NTK_O= 15 đvC

1đvC = 1,6605^-24

=> 16đvC = 1,6605^-24.16 =2,6568,10^-24

Answer 4

1đvc=1,6605^-24

Mà PTK O=16đvc

=> m_O =1,6605^-24 .16=2,6528.10^-24