Question

các bạn giúp mình  với      (x^4-1)^2+(x^2+1)^2

cảm ơn nhiều

 

Answer 1

`(x^4-1)^2+(x^2+1)^2`

`=x^8-2x^4+1+x^4+2x^2+1`

`=x^8-x^4+2x^2+2`

Answer 2

\(\left(x^4-1\right)^2+\left(x^2+1\right)^2=\left(x^2-1\right)^2.\left(x^2+1\right)^2+\left(x^2+1\right)^2\)

\(=\left(x^2+1\right)^2\left[\left(x^2-1\right)^2+1\right]=\left(x^2+1\right)^2\left(x^4-2x^2+2\right)\)

Answer 3

`(x^4-1)^2+(x^2+1)^2`

`=[(x^2)^2-1^2]^2+(x^2+1)^2`

`=(x^2+1)^2 .(x^2-1)^2 +(x^2+1)^2`

`=(x^2+1)^2 [(x^2-1)^2+1]`