a) x-(-18-x)=x-22
<=> x+18+x=x-22<=> x=-40
b) 18-[19+(-x)]=x-(19+x)+18
<=> 18-19+x=x-19-x+18
<=> x=0
Ta có :
a.x-(-18-x)=x-22
→x+18+x=x-22
→x+x+18=x-22
→2x+18=x-22
→2x-x=-22-18
→x=-40
Vậy x=-40
b. 18-[19+(-x)]=x-(19+x)+18
→18-19+x=x-19-x+18
→-1+x=(x-x)-(19-18)
→-1+x=-1
→x=0
Vậy x=0