Bài 3:
a: Ta có: \(A=\left(3x+7\right)\left(2x+3\right)-\left(3x-5\right)\left(2x+11\right)\)
\(=6x^2+9x+14x+21-6x^2-33x+10x+55\)
=76
b: Ta có: \(B=\left(x-3\right)\left(x+2\right)-\left(x-5\right)\left(x+4\right)\)
\(=x^2+2x-3x-6-x^2-4x+5x+20\)
=14
Bài 1:
a) \(\left(x+2\right)\left(x-3\right)=x^2-x-6\)
b) \(\left(x^2-1\right)\left(x+2\right)=x^3+2x^2-x-2\)
c) \(\left(x^2+2x\right)\left(x^2-1\right)=x^4+2x^3-x^2-2x\)
d) \(\left(x+1\right)\left(x^2-x+1\right)=x^3+1\)
e) \(\left(x^2-2x+3\right)\left(x-4\right)=x^3-6x^2+11x-12\)