Question

BT2: Tìm x, biết:

4) \(\text{|}\text{|}2x-1\text{|}-3\text{|}=1\)

Answer 1

\(\left|\left|2\text{x}-1\right|-3\right|=1\)

*TH1 :

=> |2x-1| - 3 = 1

=> | 2x-1 | = 4

+Th1 :

2x-1 = 4

=> 2x = 5

=> x= \(\dfrac{5}{2}\)

+Th2 :

2x - 1 = -4

=> 2x = -3

=> x= \(\dfrac{-3}{2}\)

*TH2 :

| 2x-1 | - 3 = -1

=> | 2x - 1 | = 2

+Th1 :

2x- 1 = 2

=> 2x = 3

=> x = \(\dfrac{3}{2}\)

+Th2 :

2x - 1 = -2

=> 2x = -1

=> x = \(\dfrac{-1}{2}\)

Vậy : x = \(\dfrac{-1}{2}\) hoặc x = \(\dfrac{5}{2}\) hoặc x= \(\dfrac{3}{2}\) hoặc x = \(\dfrac{-3}{2}\)