\(\dfrac{x+2017}{x+2018}=\dfrac{2022}{2023}\)
\(\Leftrightarrow2023x+4080391=2022x+4080396\)
=>x=5
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Chương I : Số hữu tỉ. Số thực
Các câu hỏi tương tự
BT1: Tìm x, biết:
6) \(\dfrac{x+1}{2017}+\dfrac{x+2}{2016}=\dfrac{x+3}{2015}-1\)
tìm x biết
a) dfrac{1}{2}x+2dfrac{1}{2}3dfrac{1}{2}x-dfrac{3}{4}
b) dfrac{2}{3}x-dfrac{2}{5}dfrac{1}{2}x-dfrac{1}{3}
c) dfrac{1}{3}x+dfrac{2}{5}left(x+1right)0
d) dfrac{2}{3}-dfrac{1}{3}left(x-dfrac{3}{2}right)-dfrac{1}{2}left(2x+1right)5
e) dfrac{x+2015}{5}+dfrac{x+2016}{4}dfrac{x+2017}{3}+dfrac{x+2018}{2}
Đọc tiếp
tìm x biết
a) \(\dfrac{1}{2}x+2\dfrac{1}{2}=3\dfrac{1}{2}x-\dfrac{3}{4}\)
b) \(\dfrac{2}{3}x-\dfrac{2}{5}=\dfrac{1}{2}x-\dfrac{1}{3}\)
c) \(\dfrac{1}{3}x+\dfrac{2}{5}\left(x+1\right)=0\)
d) \(\dfrac{2}{3}-\dfrac{1}{3}\left(x-\dfrac{3}{2}\right)-\dfrac{1}{2}\left(2x+1\right)=5\)
e) \(\dfrac{x+2015}{5}+\dfrac{x+2016}{4}=\dfrac{x+2017}{3}+\dfrac{x+2018}{2}\)
BT1: Tìm x, biết:
3) \(\dfrac{1}{2}\text{|}\dfrac{1}{3}x-\dfrac{1}{4}\text{|}-\dfrac{1}{5}=\dfrac{1}{6}\)
BT1: Tìm x, biết:
5) \(\text{|}x+\dfrac{1}{2}\text{|}+\text{|}x+\dfrac{1}{3}\text{|}+\text{|}x+\dfrac{1}{4}\text{|}=4x\)
BT1: Tìm x, biết:
1) \(\left[\left(\dfrac{1}{2}x-\dfrac{1}{3}\right)^2+\dfrac{1}{4}\right]^3=\dfrac{1}{8}\)
BT1: Tìm x, biết:
2) \(9-\left(\dfrac{2}{3}-x\right)=-\dfrac{5}{4}\)
BT1: Tìm x, biết:
3) \(\text{|}\text{|}\dfrac{1}{2}.x-\dfrac{1}{4}\text{|}-3\text{|}=4\)
BT1: Tìm x, biết:
1) \(x+\dfrac{1}{4}=\dfrac{3}{5}-\left(-\dfrac{1}{3}\right)\)
BT1: Tìm x, biết:
5) \(\dfrac{1}{2}+\dfrac{1}{3}< x\le1\dfrac{1}{2}+\dfrac{1}{5}\left(x\in Z\right)\)