Question

B=\(\left(\frac{\sqrt{x}}{\sqrt{x}-2}-\frac{4}{x-2\sqrt{x}}\right).\left(\frac{1}{\sqrt{x}+2}+\frac{4}{x-4}\right)\)

Rút gọn

Answer 1

B= \(\left(\frac{\sqrt{x}}{\sqrt{x}-2}-\frac{4}{x-2\sqrt{2}}\right):\left(\frac{1}{\sqrt{x}+2}+\frac{4}{x-4}\right)\)

= \(\left(\frac{\sqrt{x}}{\sqrt{x}-2}+\frac{4}{\sqrt{x}\left(\sqrt{x}-2\right)}\right):\left(\frac{\sqrt{x}-2+4}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-2\right)}\right)\)

= \(\frac{x-4}{\sqrt{x}\left(\sqrt{x}-2\right)}\):\(\frac{1}{\sqrt{x}-2}\)

=\(\frac{\sqrt{x}+2}{\sqrt{x}}.\sqrt{x}-2\)

Nhớ tick cho mk nhé

=\(\frac{x-4}{\sqrt{x}}\)

Answer 2

Mk đang cần gấp nhé