\(n_{C4H10}=\frac{13,05}{58}=0,225\left(mol\right)\)
\(2C_4H_{10}+13O_2\rightarrow8CO_2+10H_2\)
\(n_{O2}=\frac{0,225.13}{2}=1,4625\left(mol\right)\)
\(V_{O2}=1,4625.22,4=32,76\left(l\right)\)
Vì VO2 = 20% Vkk
\(\Rightarrow V_{kk}=32,76.5=163,8\left(l\right)\)