\(log_7\left(4x^2-4x+1\right)-log_72x+4x^2+1=6x\)
\(\Leftrightarrow log_7\left(4x^2-4x+1\right)+4x^2-4x+1=log_72x+2x\)
\(\Rightarrow4x^2-4x+1=2x\)
\(\Rightarrow...\)
log7(4x2−4x+1)−log72x+4x2+1=6xlog7(4x2−4x+1)−log72x+4x2+1=6x
=log7(4x2−4x+1)+4x2−4x+1=log72x+2x⇔log7(4x2−4x+1)+4x2−4x+1=log72x+2x
=4x2−4x+1=2x⇒4x2−4x+1=2x
= 2x