Ta có
(x-y)=1 => (x-y)2=1
xy=1 => 4xy=4
=> (x-y)2+4xy=1+4
x2-2xy+y2+4xy=5
(x+y)2=5
=> x+y=\(\sqrt{5}\)
=>(x+y)3=5\(\sqrt{5}\)
=>x3+y3+3xy(x+y)=5\(\sqrt{5}\)
=>x3+y3+3.1.\(\sqrt{5}\) =5\(\sqrt{5}\)
=>x3+y3=2\(\sqrt{5}\)
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