a, \(n_X=\frac{13,44}{22,4}=0,6\left(mol\right)\)
\(M_X=24.2=48\left(\frac{g}{mol}\right)\)
\(\Rightarrow m_X=48.0,6=28,8\left(g\right)\)
Gọi \(\left\{{}\begin{matrix}n_{SO2}:a\left(mol\right)\\n_{O2}:b\left(mol\right)\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}64a+32b=28,8\\a+b=0,6\end{matrix}\right.\Rightarrow a=b=0,3\)
\(\Rightarrow\%V_{SO2}=V\%_{O2}=50\%\)
b,\(2SO_2+O_2\rightarrow2SO_3\)
\(n_{SO2\left(pư\right)}=a\left(mol\right)\)
\(\Rightarrow n_{O2\left(pư\right)}0,5a\left(mol\right)\)
\(n_{SO3}=a\left(mol\right)\)
\(n_{hh\left(Y\right)}=\frac{11,2}{22,4}=0,5\left(mol\right)\)
\(\Leftrightarrow0,3-a+0,3-0,5a+a=0,5\)
\(\Rightarrow a=0,2\left(mol\right)\)
\(H=\frac{0,2}{0,3}.100\%=66,67\%\)
