Question

Bài 2: (2 điểm) Tìm x, biết:
b, \(0,5x+\dfrac{2}{3}x-x=-4\)
 

Answer 1

\(\Leftrightarrow\dfrac{1}{2}x+\dfrac{2}{3}x-x=-4\Leftrightarrow\dfrac{3x+4x-6x}{6}=-\dfrac{24}{6}\)

\(\Rightarrow x=-24\)

Answer 2

b) \(x.\left(\dfrac{1}{2}+\dfrac{2}{3}-1\right)=-4\)

\(x.\dfrac{-1}{6}=-4\)

\(x=-4:\dfrac{-1}{6}\)

\(x=-24\)

Answer 3

Ta có: \(0.5x+\dfrac{2}{3}x-x=-4\)

\(\Leftrightarrow x\cdot\dfrac{1}{6}=-4\)

hay x=-24