\(\dfrac{1}{6}\left(x+\dfrac{3}{2}\right)-\dfrac{2}{3}x=\dfrac{5}{4}\)
\(\Leftrightarrow\dfrac{1}{6}x+\dfrac{1}{6}\cdot\dfrac{3}{2}-\dfrac{2}{3}x+\dfrac{5}{4}\)
\(\Leftrightarrow\dfrac{1}{6}x+\dfrac{1}{4}-\dfrac{2}{3}x=\dfrac{5}{4}\)
\(\Leftrightarrow\dfrac{1}{6}x-\dfrac{2}{3}x=\dfrac{5}{4}-\dfrac{1}{4}\)
\(\Leftrightarrow\dfrac{1}{6}x-\dfrac{2}{3}x=1\)
\(\Leftrightarrow x(\dfrac{1}{6}-\dfrac{2}{3})=1\)
\(\Leftrightarrow x\left(\dfrac{-3}{6}\right)=1\)
\(\Leftrightarrow x=1:(\dfrac{-3}{6})\)
\(\Leftrightarrow x=-2\)
Lời giải:
\(\dfrac{1}{6}\left(x+\dfrac{3}{2}\right)-\dfrac{2}{3}x=\dfrac{5}{4}\)
\(\Rightarrow\dfrac{1}{6}x+\dfrac{1}{4}-\dfrac{2}{3}x=\dfrac{5}{4}\)
\(\Rightarrow\dfrac{1}{6}x-\dfrac{2}{3}x=\dfrac{5}{4}-\dfrac{1}{4}\)
\(\Rightarrow\dfrac{-1}{2}x=1\)
\(\Rightarrow x=-2\)
\(\dfrac{1}{6}\)(\(x\) + \(\dfrac{3}{2}\)) - \(\dfrac{2}{3}\)\(x\) = \(\dfrac{5}{4}\)
\(\dfrac{1}{6}\)\(x\) + \(\dfrac{1}{6}\) * \(\dfrac{3}{2}\) - \(\dfrac{2}{3}x\) = \(\dfrac{5}{4}\)
\(\dfrac{1}{6}x\) - \(\dfrac{2}{3}\)\(x\) + \(\dfrac{1}{4}\) = \(\dfrac{5}{4}\)
\(\dfrac{1}{6}x\) - \(\dfrac{2}{3}x\) = \(\dfrac{5}{4}\) - \(\dfrac{1}{4}\)
\(\dfrac{1}{6}x\) - \(\dfrac{2}{3}x\) = 1
(\(\dfrac{1}{6}\) - \(\dfrac{2}{3}\))\(x\) = 1
\(\dfrac{-1}{2}x\) = 1
\(x\) = 1 / \(\dfrac{-1}{2}\)
\(x\) = -2
