a: =2(x^2+2x+9/2)
=2(x^2+2x+1+7/2)
=2(x+1)^2+7>=7
Dấu = xảy ra khi x=-1
b: \(=2\left(\dfrac{3}{2}x^2-2xy+y^2-\dfrac{3}{2}x+\dfrac{2007}{2}\right)\)
\(=2\left(x^2-2xy+y^2+\dfrac{1}{2}x^2-\dfrac{3}{2}x+\dfrac{2007}{2}\right)\)
\(=2\left(x-y\right)^2+x^2-3x+2007\)
\(=2\left(x-y\right)^2+\left(x-\dfrac{3}{2}\right)^2+2004.75>=2004.75\)
Dấu = xảy ra khi x=y=3/2