Question

Bài 1:Phân tích đa thức thành nhân tử

a)a^2+2ab+b^2-c^2+2cd-d^2

b)x^2-4xy+4y^2-x+2y

Answer 1

a) Ta có: \(a^2+2ab+b^2-c^2+2cd-d^2\)

\(=\left(a^2+2ab+b^2\right)-\left(c^2-2cd+d^2\right)\)

\(=\left(a+b\right)^2-\left(c-d\right)^2\)

\(=\left(a+b-c+d\right)\left(a+b+c-d\right)\)

b) Ta có: \(x^2-4xy+4y^2-x+2y\)

\(=\left(x-2y\right)^2-\left(x-2y\right)\)

\(=\left(x-2y\right)\left(x-2y-1\right)\)