Question

bai 1:Chuyen tong thanh tich a,\(x^2+5x+6\) b,\(2x^2+5x+3\)

c,\(x^2-10x+16\) d,\(4x^2+9x+5\)

bai 2 :a, \(A=x^2-3x\) b, \(B=\dfrac{x+1}{2+x}\) c, \(C=\dfrac{x-1}{x^2+5}\)

Answer 1

Bài 1:

a) \(x^2+5x+6=x^2+2x+3x+6=x\left(x+2\right)+3\left(x+2\right)=\left(x+2\right)\left(x+3\right)\)

b) \(2x^2+5x+3=2x^2+2x+3x+3=2x\left(x+1\right)+3\left(x+1\right)=\left(x+1\right)\left(2x+3\right)\)

c) \(x^2-10x+16=x^2-2x-8x+16=x\left(x-2\right)-8\left(x-2\right)=\left(x-2\right)\left(x-8\right)\)

d) \(4x^2+9x+5=4x^2+4x+5x+5=4x\left(x+1\right)+5\left(x+1\right)=\left(x+1\right)\left(4x+5\right)\)

Bài 2:

không rõ đề --> k lm