Do |a| = 1,5 => \(\left[\begin{array}{nghiempt}a=1,5\\a=-1,5\end{array}\right.\) => a2 = (1,5)2 = \(\frac{9}{4}\)
Thay a = \(\frac{9}{4}\); b = -0,75, t có: \(P=\left(-2\right):\frac{9}{4}-\left(-0,75\right).\frac{2}{3}\)
\(P=\left(-2\right).\frac{4}{9}-\frac{-3}{4}.\frac{2}{3}\)
\(P=\frac{-8}{9}-\frac{-1}{2}\)
\(P=\frac{-8}{9}+\frac{1}{2}\)
\(P=\frac{-16}{18}+\frac{9}{18}=\frac{-7}{18}\)