Question

Bài 14: Tính x biết :

m) \(\frac{3}{4}-x=\frac{1}{5}\)           o)    \(\frac{3}{5}x+\frac{1}{4}=\frac{1}{10}\)             p)     \(-\frac{4}{3}x+\frac{3}{2}=\frac{5}{6}\)

Answer 1

m) \(\frac{3}{4}-x=\frac{1}{5}\)

\(x=\frac{3}{4}-\frac{1}{5}\)

\(x=\frac{11}{20}\)

Vậy \(x=\frac{11}{20}\)

o) \(\frac{3}{5}x+\frac{1}{4}=\frac{1}{10}\)

\(\frac{3}{5}x=\frac{1}{10}-\frac{1}{4}\)

\(\frac{3}{5}x=-\frac{3}{20}\)

\(x=\left(-\frac{3}{20}\right):\frac{3}{5}\)

\(x=-\frac{1}{4}\)

Vậy \(x=-\frac{1}{4}\)

p) \(-\frac{4}{3}x+\frac{3}{2}=\frac{5}{6}\)

\(-\frac{4}{3}x=\frac{5}{6}-\frac{3}{2}\)

\(-\frac{4}{3}x=-\frac{2}{3}\)

\(x=\left(-\frac{2}{3}\right):\left(-\frac{4}{3}\right)\)

\(x=\frac{1}{2}\)

Vậy \(x=\frac{1}{2}\)

Answer 2

m) \(\frac{3}{4}\) - x = \(\frac{1}{5}\)

            x= \(\frac{3}{4}\) - \(\frac{1}{5}\)

            x= \(\frac{11}{20}\)

o) \(\frac{3}{5}\)x + \(\frac{1}{4}\) = \(\frac{1}{10}\)

            \(\frac{3}{5}\)x = \(\frac{1}{10}\) - \(\frac{1}{4}\)

            \(\frac{3}{5}\)x = -\(\frac{3}{20}\)

               x = \(\frac{-3}{20}\):\(\frac{3}{5}\)

               x = \(\frac{-1}{4}\)

p) \(\frac{-4}{3}\)x + \(\frac{3}{2}\) = \(\frac{5}{6}\)

            \(\frac{-4}{3}\)x = \(\frac{5}{6}\) - \(\frac{3}{2}\)

            \(\frac{-4}{3}\)x = \(\frac{-2}{3}\)

                 x = \(\frac{-2}{3}\) : \(\frac{-4}{3}\)

                 x = \(\frac{1}{2}\)

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