1) \(\frac{3}{4}-x=\frac{1}{5}\)<=> x=\(\frac{3}{4}-\frac{1}{5}=\frac{11}{20}\)
2) \(\frac{7}{2}+2x=-\frac{3}{4}\)<=> 2x=\(-\frac{3}{4}-\frac{7}{2}=-\frac{17}{4}\)<=> \(x=-\frac{17}{8}\)
3) \(\frac{1}{3}+\frac{2x}{3}=\frac{4}{3}\)<=> 1+2x=4<=> 2x=3<=> x=3/2
1) \(\frac{3}{4}-x=\frac{1}{5}\)
\(x=\frac{3}{4}-\frac{1}{5}\)
\(x=\frac{11}{20}\)
2)\(\frac{7}{2}+2x=\frac{-3}{4}\)
\(2x=\frac{-3}{4}-\frac{7}{2}\)
\(2x=-\frac{17}{4}\)
\(x=-\frac{17}{4}:2\)
\(x=-\frac{17}{8}\)
3)\(\frac{1}{3}+\frac{2}{3}x=\frac{4}{3}\)
\(\frac{2}{3}x=\frac{4}{3}-\frac{1}{3}\)
\(\frac{2}{3}x=1\)
\(x=1:\frac{2}{3}\)
\(x=\frac{3}{2}\)
^...^ ^_^
k) \(\frac{3}{4}\) - x = \(\frac{1}{5}\)
x = \(\frac{3}{4}\) - \(\frac{1}{5}\)
x = \(\frac{11}{20}\)
l) \(\frac{7}{2}\) + 2.x = \(\frac{-3}{4}\)
\(\frac{7}{2}\) + 2x = \(\frac{-3}{4}\)
2x = \(\frac{-3}{4}\) -\(\frac{7}{2}\)
2x = \(\frac{-17}{4}\)
x = \(\frac{-17}{4}\) : 2
x = \(\frac{-17}{8}\)
m) Lặp lại câu k
n) \(\frac{1}{3}\) + \(\frac{2}{3}\).x = \(\frac{4}{3}\)
\(\frac{1}{3}\) + \(\frac{2}{3}\)x = \(\frac{4}{3}\)
\(\frac{2}{3}\)x = \(\frac{4}{3}\) - \(\frac{1}{3}\)
\(\frac{2}{3}\)x = 1
x = 1 : \(\frac{2}{3}\)
x = \(\frac{3}{2}\)
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