Question

Bài 14 : Tìm x biết :

e) \(\frac{-2}{3}-\frac{1}{3}\left(2x-5\right)=\frac{3}{2}\)          g) \(\frac{2}{5}x+\frac{1}{2}=\frac{-3}{4}\)         h) \(\frac{1}{3}x-8=\frac{1}{2}\)       i) \(x-\frac{1}{4}=\frac{5}{8}.\frac{2}{3}\)

Answer 1

e)\(\frac{1}{3}\left(2x-5\right)=-\frac{2}{3}-\frac{3}{2}\)

\(\frac{1}{3}\left(2x-5\right)=-\frac{13}{6}\)

\(2x-5=-\frac{13}{2}\)

\(2x=\frac{-3}{2}\)

\(x=-\frac{3}{4}\)

Answer 2

g)\(\frac{2}{5}x=\frac{-3}{4}-\frac{1}{2}\)

\(\frac{2}{5}x=\frac{-5}{4}\)

\(x=\frac{-25}{8}\)

Answer 3

h)\(\frac{1}{3}x=\frac{1}{2}+8\)

\(\frac{1}{3}x=\frac{17}{2}\)

\(x=\frac{51}{2}\)

Answer 4

i)\(x-\frac{1}{4}=\frac{5}{12}\)

\(x=\frac{5}{12}+\frac{1}{4}\)

\(x=\frac{2}{3}\)

Answer 5

h) \(\frac{1}{3}\)x - 8 = \(\frac{1}{2}\)

          \(\frac{1}{3}\)x = \(\frac{1}{2}\) + 8

           \(\frac{1}{3}\)x = \(\frac{17}{2}\)

 

Answer 6

câu h mk làm thiếu 

mk làm lại 

h) \(\frac{1}{3}\)x -8 = \(\frac{1}{2}\)

         \(\frac{1}{3}\)x = \(\frac{1}{2}\) + 8

         \(\frac{1}{3}\)x = \(\frac{17}{2}\)

             x = \(\frac{17}{2}\) : \(\frac{1}{3}\)

             x = \(\frac{51}{2}\)

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