Đặt :
\(A=\dfrac{2a+9}{a+3}+\dfrac{5a+17}{a+3}-\dfrac{3a}{a+3}\)
\(=\dfrac{2a+9+5a+19-3a}{a+3}\)
\(=\dfrac{-6a-8}{a+3}\)
\(\dfrac{-6a+18-10}{a+3}=\dfrac{10}{a+3}-\dfrac{6\left(a+3\right)}{a+3}=\dfrac{10}{a+3}-6\)
\(A\in Z\Leftrightarrow\dfrac{10}{a+3}\in Z\)
\(\Leftrightarrow a+3⋮10\)
\(\Leftrightarrow a+3\inƯ\left(10\right)\)
Lập bảng :v