a)123+236+77+164 =(123+77)+(236+164)=200+400=600
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a) Ta có: 123+236+77+164
=(123+77)+(236+164)
=200+400=600
b) Ta có: \(2^5\cdot2^3-\frac{3^{13}}{3^8}\)
\(=2^8-3^5=256-243=13\)
c) Ta có \(239\cdot147-239\cdot47\)
\(=239\left(147-47\right)=239\cdot100=23900\)
d) Ta có: \(22\cdot31-\frac{\left(1^{2012}+2012^0\right)}{\left|-2\right|}\)
\(=22\cdot31-\frac{1+1}{2}=22\cdot31-1=682-1=681\)
