Question

bài 1: thu gọn đa thức

A= x³*(\(\frac{-5}{4}\)x²y)*(\(\frac{2}{5}\)x³y⁴)

B=(\(\frac{-3}{4}\)x⁵y⁴)*(xy²)*(\(\frac{-8}{9}\)x²y⁵)

Answer 1

A=\(\left(-\frac{5}{4}\times\frac{2}{5}\right)\times\left(x^3x^2x^3\right)\times\left(yy^4\right)\)

A=\(-\frac{1}{2}x^8y^5\)

Answer 2

B=\(\left(-\frac{3}{4}\times-\frac{8}{9}\right)\times\left(x^5xx^2\right)\times\left(y^4y^2y^5\right)\)

B=\(\frac{2}{3}x^8y^{11}\)