a)
\(\left(a\right)\Leftrightarrow\dfrac{x+1}{x-1}\le0\Rightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x+1\ge0\\x-1< 0\end{matrix}\right.\\\left\{{}\begin{matrix}x+1\le0\\x-1\ge0\end{matrix}\right.\end{matrix}\right.\)
(I) \(\Rightarrow\left\{{}\begin{matrix}x\ge-1\\x< 1\end{matrix}\right.\) \(\Rightarrow-1\le x< 1\)
(II)\(\Rightarrow\left\{{}\begin{matrix}x\le-1\\x>1\end{matrix}\right.\) vô nghiệm
Kết luận ;\(-1\le x< 1\)
\(\left(b\right)\Leftrightarrow\dfrac{2x+3}{5x-2}\ge0\Rightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}2x+3\ge0\\5x-2>0\end{matrix}\right.\\\left\{{}\begin{matrix}2x+3\le0\\5x-2< 0\end{matrix}\right.\end{matrix}\right.\)
(I)\(\Rightarrow x\le-\dfrac{3}{2}\)
(II)\(\Rightarrow x>\dfrac{2}{5}\)
Kết luận nghiệm \(\left[{}\begin{matrix}x\le-\dfrac{3}{2}\\x>\dfrac{2}{5}\end{matrix}\right.\)
