a, A=\(-x^2+2xy-2\)\(+3x^2+xy+2\)
=(-x\(^2\)+3x\(^2\))+(2xy+xy)+(-2+2)
=2x\(^2\)+3xy
B=(\(x^2-2y+2\))-(\(-x^2+2xy-1\))
=\(x^2-2y+2\)\(+x^2-2xy+1\)
=\(\left(x^2+x^2\right)\)-2y-2xy+(2+1)
= 2x\(^2\) -2y-2xy+3
b,*thay x=1,y=5 vào A
ta có A=2.1\(^2\)+3.1.5
=17
*thay x=1, y=5 vào B
ta có B=2.1\(^2\)-2.5-2.1.5+3
=-15