\(R=\left(1+\dfrac{x+\sqrt{x}}{1+\sqrt{x}}\right).\left(1+\dfrac{x-\sqrt{x}}{1-\sqrt{x}}\right)\)
\(ĐK:x\ge0;x\ne1\)
\(R=\left(1+\dfrac{\sqrt{x}\left(\sqrt{x}+1\right)}{1+\sqrt{x}}\right).\left(1+\dfrac{\sqrt{x}\left(\sqrt{x}-1\right)}{1-\sqrt{x}}\right)\)
\(R=\left(1+\sqrt{x}\right)\left(1-\sqrt{x}\right)\)
\(R=1-x\)
\(x=-5\)
\(\Rightarrow R=1-\left(-5\right)=6\)
Nhưng \(x\ge0\) \(\Leftrightarrow\) R vô nghĩa