bài 1 : cac phương trinh sau
a,\(\left(2x-4\right)\left(\dfrac{7x+2}{5}+\dfrac{2\left(1-3x\right)}{3}\right)\)
b, \(\left(2x-1\right)^2+2\left(2-x\right)\left(2x-1\right)=0\)
c, \(x^3+1=x\left(x+1\right)\)
d, \(x^3-\dfrac{1}{4}x\)
e, \(4x^2-1=0\)
g, (\(2x-1)^2-\left(x+3\right)^3\)
h, \(x\left(x^2-5\right)^2-4x=0\)
i, \(x^2-4+\left(x-2\right)^2\)
k, (x-1)(5x+3)=(3x-8)(x-1)
l, \(x^3+x^2+x+1=0\)
Các bạn ơi ! giúp mik với đi
b: =>(2x-1)(2x-1+4-2x)=0
=>3(2x-1)=0
=>2x-1=0
=>x=1/2
c: =>(x+1)(x^2-x+1)-x(x+1)=0
=>(x+1)(x-1)^2=0
=>x=1 hoặc x=-1
e: =>(2x-1)(2x+1)=0
=>x=1/2 hoặc x=-1/2
h: =>x[(x^2-5)^2-4]=0
=>x(x^2-7)(x^2-3)=0
=>\(x\in\left\{0;\pm\sqrt{7};\pm\sqrt{3}\right\}\)
k: =>(x-1)(5x+3-3x+8)=0
=>(x-1)(2x+11)=0
=>x=1 hoặc x=-11/2
l: =>x^2(x+1)+(x+1)=0
=>(x+1)(x^2+1)=0
=>x+1=0
=>x=-1
