\(\left(\sqrt{12}+3\sqrt{15}-4\sqrt{135}\right)\sqrt{3}\)
\(=\left(2\sqrt{3}+3\sqrt{15}-12\sqrt{15}\right)\sqrt{3}\)
\(=\left(2\sqrt{3}-9\sqrt{15}\right)\sqrt{3}\)
\(=6-9\sqrt{45}\)
\(a.\left(\sqrt{12}+3\sqrt{15}-4\sqrt{135}\right)\sqrt{3}=\left(2\sqrt{3}+3\sqrt{15}-12\sqrt{15}\right)\sqrt{3}=2.3-9\sqrt{9.5}=6-27\sqrt{5}\) \(b.\sqrt{252}-\sqrt{700}+\sqrt{1008}-\sqrt{448}=\sqrt{36.7}-\sqrt{100.7}+\sqrt{144.7}-\sqrt{64.7}=6\sqrt{7}-10\sqrt{7}+12\sqrt{7}-8\sqrt{7}=0\)