\(A=\left(\sqrt{6}-3\sqrt{3}+5\sqrt{2}-\dfrac{1}{2}\sqrt{8}\right)2\sqrt{6}-5\sqrt{3}=\left(\sqrt{6}-3\sqrt{3}+5\sqrt{2}-\sqrt{2}\right)2\sqrt{6}-5\sqrt{3}=\left(\sqrt{6}-3\sqrt{3}+4\sqrt{2}\right)2\sqrt{6}-5\sqrt{3}=12-18\sqrt{2}+16\sqrt{3}-5\sqrt{3}=12-18\sqrt{2}+11\sqrt{3}\)
\(B=\left(2\sqrt{3}-3\sqrt{2}\right)^2+2\sqrt{6}+3\sqrt{24}=12-12\sqrt{6}+18+2\sqrt{6}+6\sqrt{6}=30-4\sqrt{6}\)