Question

a,\(\left(\dfrac{-2}{3}\right)^2.x=\left(\dfrac{-2}{3}\right)^5\)

b,\(\left(\dfrac{-1}{3}\right)^3.x=\dfrac{1}{81}\)

tim x

Answer 1

\(a)\left(\dfrac{-2}{3}\right)^2.x=\left(\dfrac{-2}{3}\right)^5\)

\(\Rightarrow x=\left(\dfrac{-2}{3}\right)^5:\left(\dfrac{-2}{3}\right)^2\)

\(\Rightarrow x=\left(\dfrac{-2}{3}\right)^3\)

Vậy ...............

\(b)\left(-\dfrac{1}{3}\right)^3.x=\dfrac{1}{81}\)

\(\Rightarrow\dfrac{-1}{27}.x=\dfrac{1}{81}\)

\(\Rightarrow x=\dfrac{1}{81}:\dfrac{-1}{27}\)

\(\Rightarrow x=\dfrac{-1}{3}\)

Vậy ..................

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