Question

a/ (x+2)(2-2x)-(2x+1)(3-x)=0

b/(x-4)(x²-2)=0

c/\(\dfrac{3x+1}{4}-x-1=\dfrac{4-3x}{3}\)

Answer 1

a/

\(\left(x+2\right)\left(2-2x\right)-\left(2x+1\right)\left(3-x\right)=0\)

\(\Leftrightarrow-2x-2x^2+4-5x+2x^2-3=0\)

\(\Leftrightarrow-7x+1=0\)

\(\Leftrightarrow\dfrac{1}{7}\)

Answer 2

c/

\(\dfrac{3x+1}{4}-x-1=\dfrac{4-3x}{3}\)

\(\Leftrightarrow\dfrac{3.\left(3x+1\right)}{12}-\dfrac{12x}{12}-\dfrac{12}{12}=\dfrac{4.\left(4-3x\right)}{12}\)

\(\Leftrightarrow9x+3-12x-12-16+12x=0\)

\(\Leftrightarrow9x-25=0\)

\(\Leftrightarrow x=\dfrac{25}{9}\)