Question

a) - x - \(\dfrac{2}{3}=-\dfrac{6}{7}\) b) (5x - 1). (2x - \(\dfrac{1}{3}=0\)

Answer 1

a/ \(-x-\dfrac{2}{3}=-\dfrac{6}{7}\)

\(\Leftrightarrow-x=-\dfrac{6}{7}+\dfrac{2}{3}\)

\(\Leftrightarrow-x=-\dfrac{18}{21}+\dfrac{14}{21}\)

\(\Leftrightarrow-x=-\dfrac{4}{21}\)

\(\Leftrightarrow x=\dfrac{4}{21}\)

Vậy ....

b/ \(\left(5x-1\right)\left(2x-\dfrac{1}{3}\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}5x-1=0\\2x-\dfrac{1}{3}=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}5x=1\\2x=\dfrac{1}{3}\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{5}\\x=\dfrac{1}{6}\end{matrix}\right.\)

Vậy ..