a.
\(\%_C=\frac{12}{12+16+16.2}.\text{100%=20%}\)
\(\%_O=\frac{16}{12+16+16.2}.\text{100%=26,67%}\)
\(\%_N=\frac{14.2}{12+16+16.2}.100\%=\text{46,67%}\)
\(\%_H=\text{100%- 20%-26,67%-46,67%=6,66%}\)
b)
+ Theo câu "a" trong 100g Ure chứa 46.67 g Nito
⇒ 10g Ure chứa 4.667 g Nito