a) Ta có: \(3\frac{1}{2}+\frac{2014}{2015}-0,5+\frac{1}{2015}\)
\(=\frac{7}{2}-\frac{1}{2}+1\)
\(=3+1=4\)
b) Ta có: \(85\%\cdot x+25\%\cdot x=110\)
\(\Leftrightarrow x\left(85\%+25\%\right)=110\)
\(\Leftrightarrow x\cdot110\%=110\)
\(\Leftrightarrow x\cdot\frac{11}{10}=110\)
hay \(x=110:\frac{11}{10}=110\cdot\frac{10}{11}=100\)
Vậy: x=100